Ashop only buys bananas with the lengths between 13 cm and 20 cm. estimate the fraction of the 80 bananas that the shop buys

Step-by-step explanation:

We know that the shop only buys abanans with lengths between 13 cm and 20 cm.

So, the fraction of the 80 bananas is actually a ratio between the y-values of each lenth (13 and 20 cm) and the total 80. First, let's see which y-values belong to each length.

Notice that 13 belons to 20 at Cumulative Frequency. And 20 belongs to 62. So, the pairs are (13,20) and (20,62).

This fraction means that the shop only buys 42 bananas out of 80, because those are between 13 cm and 20 cm.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1