Two independent simple random samples are taken to test the difference between the means of two populations whose variances are not known, but are assumed to be equal. the sample sizes are n1 = 32 and n2 = 40. the correct distribution to use is the
a. t distribution with 73 degrees of freedom
b. t distribution with 72 degrees of freedom
c. t distribution with 71 degrees of freedom
d. t distribution with 70 degrees of freedom

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

Hey, can you post the problem?

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