Acube with 15-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (round your answers to the nearest whole number. use 9.8 m/s2 for the acceleration due to gravity. recall that the weight density of water is 1000 kg/m3.) (a) estimate the hydrostatic force on the top of the cube. n (b) estimate the hydrostatic force on one of the sides of the cube.

0.204 KN

Step-by-step explanation:

Height above cube h= (100-15)/100 =  0.85 m

a) force on the top of the cube = ρgh×area

= 1000×9.81×0.85 = 8330 N/m^2

= 833 KN/m^2*0.15^2= 0.187 KN

b) Force on one side of the cube

on top = 8.33 KN/m^2

at bottom ρgh

= 1000×9.8×100/100

=9800 N/m^2

Net Force =  area of the diagram

= 8.33×(15/100)^2 + 1/2(9.8-8.33)×(15/100)^2

= 0.204 KN

option: d is correct

step-by-step explanation:

i am not sure :

step-by-step explanation: