In a certain lottery, an urn contains balls numbered 1 to 26. from this urn, 6 balls are chosen randomly, without replacement. for a $1 bet, a player chooses one set of six numbers. to win, all six numbers must match those chosen from the urn. the order in which the balls are selected does not matter. what is the probability of winning this lottery with one ticket?

\frac{1}{230230}

Step-by-step explanation:

Given that in a certain lottery, an urn contains balls numbered 1 to 26

From this urn, 6 balls are chosen randomly, without replacement.

Bet amount 1 dollar and he selects a set of six numbers.

If these match with those chosen from the urn he wins (order does not matter)

Total ways of choosing 6 out of 26 =

The way he selects = 1

Hence probability of winning  =

with one ticket

b.) divide by -5.

step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm