Solve the equation for numbers 6 and 7

Question 6: x = 5/2

Question 7: b= 6

Step-by-step explanation:

Question 6:

Given that:

-2/5x + 3 = 2/3x + 1/3

Taking variables (terms with x) on left and constants on right side

Signs of transferred terms will be changed

-2/5x -2/3x = 1/3 - 3

Taking LCM on both sides

3/3*-2/5x - 2/3x*5/5 = 1/3 - 3*3/3

-6x/15 -10x/15 = (1-9)/3

-16x/15 = -8/3

Multiplying both sides by -15/16

-16x/15 * -15/16 = -8/3 * -15/16

x = 5/2

Question 7:

-2.6b + 4 = 0.9b - 17

Taking variables (terms with x) on left and constants on right side

Signs of transferred terms will be changed

-2.6b -0.9b = -17 -4

-3.5b = -21

Dividing both sides by -3.5

b = -21/-3.5

"-" sign will be cancelled out

b = 6

i hope it will help you!

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