In triangle δabc, ∠c is a right angle and cd is the height to ab. find the angles in δcbd and δcad if:
m∠a = α

m∠cdb =
m∠cbd =
m∠bcd =
m∠cda =
m∠ cad=
m∠acd =

°

°

°

°

°

°

Step-by-step explanation:

The triangles are drawn below.

Since, CD is the height to AB, therefore, CD is perpendicular to AB.

Therefore, angles °

Also, is same as .

Therefore, °

Now, triangles ΔCBD and ΔCAD are right angled triangles.

So, for the right angled triangle ΔCAD,

Now, from the figure,

From ,

Hence, all the angles of the triangles ΔCBD and ΔCAD are:

°

°

°

°

°

°

the answer will be

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