Abowl contains 10 chips, of which 8 are marked $2 each and 2 are marked $5 each. let a person choose, at random and without replacement, three chips from this bowl. if the person is to receive the sum of the resulting amounts, find his expectation.

$7.8

Step-by-step explanation:

We have three cases to this question which are;

(a). Getting two $2 and one $5

(b). Getting one $2 and two $5

(c). Getting all three $2

Note: there are 10:3 ways of doing this.

Computing the probability of each, we have:

(a). We have {8;2} {2;1} ways to get two $2. Therefore, the probability gives;

(8;2) (2;1)÷ 10;3) we get 9 here.

(b). (8;1)(2;2)÷ (10;3)

We have 12 here.

(c). (8;3)(2;0)÷ (10;3)= 6

The expectation;

(10;3)= 120, (8;3)(2;0)= 56.

(8;2)(2;1)= 56 and (8;1)(2;2)= 8.

So, the expectation is;

9.56+12.8+6.56÷120

= 936÷120

= 39÷5

= $7.8.

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

it has 4

step-by-step explanation:

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