What is the slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of `3/4`?

The slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of `3/4 is

Solution:

Given that line passes through (5, -4)

Slope "m" =

We have to find the slope intercept form

The slope intercept form is given as:

y = mx + b  ---- eqn1

where "m" is the slope of the line and "b" is the y-intercept

Here in this sum m =

Calculating y-intercept:

Substitute (x, y) = (5, -4) and "m" value in eqn 1, we get

Now eqn 1 becomes,

Hence the slope intercept form is

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for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.