He length of similar components produced by a company are approximated by a normaldistribution model with a mean of 5 cm and a standard deviation of 0.02 cm. if a component is chosen atrandoma)what is the probability that the length of this component is between 4.98 and 5.02?

0.6826894

Step-by-step explanation:

Given : The length of similar components produced by a company are approximated by a normal distribution model with a 5 cm and a 0.02 cm.

Let x be the random variable that represents the length of similar components produced by a company.

z-score :

For x= 4.98

For x= 5.02

By using the standard z-value table (right -tailed) , the probability that the length of this component is between 4.98 and 5.02 will be :_

Hence, the probability that the length of this component is between 4.98 and 5.02= 0.6826894

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step-by-step explanation:

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d