The american statistician, (vol. 53,no. 4, pp. 298–302) has an article on birth weights of babies. according to the article, the mean birth weight is 3369 grams (7 pounds, 6.5 ounces) with a standard deviation of 581 grams. (a). for samples of size 200, find the mean and standard deviation of all possible sample mean weights.(b). repeat part (a) for samples of size 400. (c). if ῡ is the mean of one of the n = 200 babies, find the probability that the mean weight is less than 2500 grams (5 pounds 8 ounces, a low birth weight). (d). if ῡ is the mean of one of the n = 400 babies, find the probability that the mean weight is less than 1500 grams (3 pounds 5 ounces, a very low birth weight).

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2