The given line passes through the points (0, -3) and (2, 3).
what is the equation, in point-slope form of the line that is
parallel to the given line and passes through the point
(-1, -1)?
y+1 = - 3(x + 1)
+1 = -(x + 1)
v+1 = $(x + 1)
5
-3 -2 1
/1
3
4
y + 1 = 3(x + 1)
save and exit
mark this and return

The equation, in point-slope form of the line that is  parallel to the given line and passes through the point  (-1, -1) is y + 1 = 3(x + 1).

Solution:

Given that, a line passes through (0, -3) and (2, 3).

We have to find the line equation which is parallel to above line and  passes through (-1, -1).

Now, let us find the slope of the given line.

So, slope of given line is 3,  

Then, slope of required line is also 3, as slopes of parallel lines are equal.

Then, required line equation in point – slope form is given as:

Hence, the line equation is y + 1 = 3(x + 1).

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94

step-by-step explanation: