85. geometry the perimeter of a rectangle is 260 meters.
the length is 30 meters greater than the width. find the
dimensions of the rectangle.

length is 126, width is 4.2

Step-by-step explanation:

P = 2 (L + W)

260 = 2(30w + w)

260 = 2(31w)

260 = 62w

w = 260/62

w = 4.19 ≅ 4.2

hence, length is 30 x 4.3 = 126

           width is 4.2

kindly mark brainliest

answer:   y=2x-3

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240