4x^2+5x-4=0 what are the real solutions

will not have real roots that means quadratic equation do not have real solution.

Solution:

Need to determine the real solutions for following quadratic equations

First let’s check whether the given quadratic equation have real roots or not

In our case, equation is

Here a = -4, b = 5 and c = -4

Substituting the values in

So since in our case which is not greater than zero, so quadratic equation will not have real roots that means quadratic equation do not have real solution.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.