![ansver](/tpl/images/cats/User.png)
Answers: 1
![ansver](/tpl/images/cats/User.png)
Answer from: Quest
Where is the diagram?
![ansver](/tpl/images/cats/User.png)
Answer from: Quest
step-by-step explanation:
we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 ï‚´10-19 c ï‚´1 v = 1.6 ï‚´10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v
![In ⊙w, vq=7, vw=3 and tq=26. find msq.](/tpl/images/05/01/IrG6X5FOVXPbgOtS.jpg)
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