Lars works as a nurse and a lumberjack. he wants to work for at most 666 days this week, and he wants to earn more than \$950$950dollar sign, 950. n+l \leq 6n+l≤6n, plus, l, is less than or equal to, 6 represents the number of days lars can work as a nurse nnn and lumberjack lll in order to work at most 666 days this week. 216n+112l > 950216n+112l> 950216, n, plus, 112, l, is greater than, 950 represents the number of days lars can work as a nurse and a lumberjack to earn more than \$950$950dollar sign, 950. does lars meet both of his expectations by working as a nurse for 222 days and working as a lumberjack for 444 days?

Lars works for the expected number of days but doesn't earn the expected amount of money.

Step-by-step explanation:

Let's check whether Lars works for the expected number of days this week by working as a nurse for 2 days and working as a lumberjack for 4 days. To do this, we substitute N=2 and L=4 into the first inequality:

N+L≤6

2+4≤6

6≤6

The true inequality shows that Lars works for the expected number of days this week by working as a nurse for 2 days and working as a lumberjack for 4 days.

Now let's check whether Lars earns the expected amount of money by working as a nurse for 2 days and working as a lumberjack for 4 days.

To do this, we substitute N=2 and L=4 into the second inequality.

216N+112L>950

216(2)+112(4) > 950

880 >950

The false inequality shows that Lars doesn't earn the expected amount of money by working as a nurse for 2 days and working as a lumberjack for 4 days.

Lars works for the expected number of days but doesn't earn the expected amount of money.

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.