Find the absolute maximum and absolute minimum values of the functionf(x)= x3 + 6x2 −63x +8over each of the indicated intervals.(a) interval = [−8,0].1. absolute maximum = 2. absolute minimum = (b) interval = [−5,4].1. absolute maximum = 2. absolute minimum = (c) interval = [−8,4].1. absolute maximum = 2. absolute minimum =

  (a) maximum = 400; minimum = 8

  (b) maximum = 348; minimum = -100

  (c) maximum = 400; minimum = -100

Step-by-step explanation:

The absolute extrema will be either at the ends of the interval or at a turning point in the interval. Here, the turning points can be found from the derivative:

  f'(x) = 3x^2 +12x -63 = 3(x^2 +4x -21)

  f'(x) = 3(x +7)(x -3)

The derivative is zero at x=-7 and at x=3. Since the cubic has a positive leading coefficient, the extreme at x=-7 is a maximum; that at x=3 is a minimum.

So, the values we are concerned with are ...

__

(a)

  1. The left turning point is in the interval, so the absolute maximum is f(-7) = 400.

  2. The absolute minimum is at the right end of the interval, at x=0. Its value is f(0) = 8.

__

(b)

  1. The absolute maximum is at the left end of the interval. Its value is f(-5) = 348.

  2. The absolute minimum is at the right turning point: f(3) = -100.

__

(c)

 1. The absolute maximum is at the left turning point: f(-7) = 400.

 2. The absolute minimum is at the right turning point: f(3) = -100.

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6

i can you with this answer

step-by-step explanation: