$6,000 dollars is invested in two different accounts earning 3% and 5% interest. at the end of one year, the two accounts earned $220 in interest. how much money was invested at 3%?

the 2 values invested are x and 6000-x

i=prt

interest=principal times rate times time

time is 1 year so t=1

r=0.03 ad 0.05

we want to find 5% so x is wha we solve for

the interests are

0.03(6000-x) and 0.05x

they add to 220

220=0.03(6000-x)+0.05x

220=180-0.3x+0.05x

220=180+0.02x

minus 180 both sides

40=0.02x

divide both sides by 0.02

2000=x

$2000 was invested at 5%

207/8 is the right

step-by-step explanation:

the true ones are a b and d