Which equation would have real zero(s) corresponding to the x-intercept(s) of the graph below?
y=-2* +4
y= 2*
y = log, (x + 2) + 1
y = log2 (-x + 2)

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

3

step-by-step explanation:

8/k

step-by-step explanation:

step-by-step explanation:

im not sure what the answer is