The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by the equation t=35cos(pi/6(m+3))+55, where m = 0 represents january 1, m = 1 represents february 1, m = 2 represents march 1, and so on. which equation also models this situation?

a) t=-35sin(pi/6m)+55

b) t=-35sin(pi/6(m+3))+55

c) t=35sin(pi/6m)+55

d) t=35sin(pi/6(m+3))+55

Answer is A.

Step-by-step explanation:

For the equation: 35cos(pi/6(m+3)+55)

Simplify it by multiplying pi/6 in the bracket values:  

Now suppose x = m.pi/6+55, while pi/2 = 90⁰

As per law cos(x+90⁰)=-sin(x)

so,

cos((m.pi/6)+55+90⁰=-sin((m.pi/6)+55)

Hence answer will be

.

The law cos(x+90⁰)=-sin(x) can be proved by putting y=90⁰ in the following formula,

cos(x+y)=cos(x).cos(y)-sin(x).sin(y)

step-by-step explanation:

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