Asurvey of a random sample of 1,500 young americans found that 87% had earned their high school diploma. based on these results, the 95% confidence interval for the proportion of young americans who have earned their high school diploma is (0.853,0.887) what is the margin of error for this confidence interval?
a. 0.95
b. 0.017
c. 0.034
d. 0.87

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

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d

step-by-step explanation:

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)