What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? check all that apply. y = −two-fifthsx − 1 2x + 5y = −5 y = −two-fifthsx − 3 2x + 5y = −15 y − 1= −two-fifths(x + 5)

2x + 5y = -5

Step-by-step explanation:

Since the new line is parallel to the given line 2x + 5y = 10, the equation of the new line has exactly the same form as does 2x + 5y = 10, except that the constant will be different.

Were we to solve this equation (in standard form) for y in slope-intercept form, we'd get:

5y = -2x + 10, or

        -2x + 10

y =

              5

or

y =  (-2/5)x + 2

Writing out 2x + 5y = C, we substitute -5 for x and 1 for y, obtaining

2x + 5y = C  =>  2(-5) + 5(1) = -10 + 5 = -5.  Therefore, C = -5 and the equation of the new line is

2x + 5y = -5

whats the question?

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they go with it happens or they mite give a chance?

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