In a carnival game, a person wages $2 on the roll of two dice. if the total of the dice is 2,3,4,5,6 then the person gets $4. if the total of the dice is 8,9,10,11,12 then the person loses $2. if the total of the two dice is 7, the person loses $0.25. what is the expected value of playing the game once?

the answer is c. hope this !

step-by-step explanation:

quit

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a