It's due tmrw
which sequence of transformations establishes that triangle qrs is congruent to triangle q'r's?

B

If you just use you finger to keep track of one point and follow each set of instructions you will find that B is correct.

I realize that in a previous comment I had said im bad at geometry but I immediately assumed this had to do with ASA and such.

the balance is found at the link

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)