Ariel left her home at 9 a. m., driving at 45 mph. at 11 a. m. her brother left the home and started after her at 60 mph. at what time did ariel's brother catch up with ariel?

5:00 pm

Step-by-step explanation:

Let

x -----> the umber of hours

y ----> the total distance in miles

we know that

The distance is equal to the speed multiplied by the time

Find out the distance traveled by Ariel at 11:00 am

11:00 am-09:00 am=2 hours

45(2)=90 miles

so

Ariel's linear equation is

----> equation A

Ariel's brother linear equation is

----> equation B

Equate equation A and equation B

Solve for x

Adds 11:00 am + 6 hours=17:00 =5:00 pm

5:00 pm

Step-by-step explanation:

Let

x > the umber of hours

y > the total distance in miles

we know that

The distance is equal to the speed multiplied by the time

Find out the distance traveled by Ariel at 11:00 am

11:00 am-09:00 am=2 hours

45(2)=90 miles

so

Ariel's linear equation is

> equation A

Ariel's brother linear equation is

> equation B

Equate equation A and equation B

Solve for x

Adds 11:00 am + 6 hours=17:00 =5:00 pm

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

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