4
1
Mathematics, 06.11.2019 05:31 fgcherubin
6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u=
4
1
u, equals, start fraction, 1, divided by, 4, end fraction.
Answers: 1
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6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u=
4
1
4
1
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