Nasa is conducting an experiment to find out the fraction of people who black out at g forces greater than 6. in an earlier study, the population proportion was estimated to be 0.46. how large a sample would be required in order to estimate the fraction of people who black out at 6 or more gs at the 98% confidence level with an error of at most 0.03?

1499

Step-by-step explanation:

As per given , we have

Prior Population proportion :

Significance level :

Critical value for 98% confidence interval (refer to z-value table) =

Margin of error :

Formula for sample size :

Therefore , the required minimum sample size = 1499

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

i think the answer would be c