Grades in large classes are sometimes approximately normally distributed—a fact that serves as the justification for "grading on a bell curve." a common practice for very large classes is to give 16% of students a grades, 34% b grades, 34% c grades, and 16% d and f grades. assuming a normal distribution of grades, what are the z-scores for these letter grades?

Grade A:

Grade B:

Grade C:

Grade D:

Step-by-step explanation:

Problems of normally distributed samples can be solved using the Z score table.

The Z score of a measure represents how many standard deviations it is above or below the mean of all the measures.

Each Z score has a pvalue. This represents the percentile of the measure.

In this problem, we have that:

The upper 16% of the class get A grades. The upper 16% has a pvalue of at least 100% = 16% = 84% = 0.84. This is .

The middle 34% of the class get B grades. The middle 34% has a pvalue of at least 84%-35% = 50% = 0.5 and at most 0.84. This is .

Those between a pvalue of 0.5-0.34 = 0.16 and 0.5 get get grade C. has a pvalue of 0.16. So a grade C is in the interval .

Those with Z lesser than -1 get grades D and F

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.