Write the equation of a line that is perpendicular to y=7/5x+6 and that passes through the line (2,-6)

The Answer is: y = -5/7x - 4 4/7

Step-by-step explanation:

The given equation:

y = 7/5x + 6

The slope is: 7/5

The slope of a line perpendicular to this line is the negative inverse:

-5/7

Take the given point, (2, -6) and use the point slope form of the equation:

y - y1 = m(x - x1)

y - (-6) = -5/7(x - 2)

y + 6 = -5/7x + 10/7

Subtract 6 from both sides:

y = -5/7x + 10/7 - 6

Find a common denominator:

y = -5/7x + 10/7 - 42/7

y = -5/7x -32/7

y = -5/7x - 4 4/7

answer: a rhombus has two lines of symmetry that run through one vertex to the one directly across it. unlike a square, planes through the center of each edge of a rhombus do not yield mirrored sides.

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this