Let s = fa; b; c; d; e; f; gg be a collection of objects with benefit-weight values as follows: a: (12; 4); b: (10; 6); c: (8; 5); d: (11; 7); e: (14; 3); f : (7; 1); g: (9; 6). what is an optimal solution to the fractional knapsack problem for s assuming we have a sack that can hold objects with total weight 18? show your work.

d is correct

step-by-step explanation:

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

pls mark as brainliest

its kind of blurry. can you put a clearer pic?

step-by-step explanation:

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).