Which two points are on the graph of m(a) = - 3/4a-12?
choose exactly two answers that are correct.
(-9,0)
(-16, 0)
(0, 12)
(0, -12)

(-16, 0) and  (0,-12)  are exactly two points on the graph of the given equation.

Step-by-step explanation:

Here, the given expression is :

Here, let M(a)  = b

⇒The equation becomes

Now, check for all the given points for (a,b)

1) FOR (-9,0)

Hence, (-9,0) is NOT on the graph.

2) FOR (-16,0)

Here, LHS = b = 0

and

Hence, LHS  =  RHS = 0  So, (-16,0) is  on the graph.

3) FOR (0,12)

Here, LHS = b = 12

Hence, (0,12) is NOT on the graph.

4) FOR (0,-12)

Here, LHS = b = -12

and LHS = RHS = -12

Hence, (0,-12) is  on the graph.

Hence, (-16, 0) and  (0,-12)  are exactly two points on the graph of the given equation.

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?