The decay of 192 mg of an isotope is given by a(t)= 192e-0.015t, where t is time in years. find the amount left after 55 years. round your answer to the nearest whole number.

a 83

b 84

c 42

d 189

This is a typical radioactive decay problem which uses the general form:

A = A0e^(-kt)

So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:

A = 192e^(-0.015*55)

A = 84 mg

squares, rhombus, rectangles

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo