Mr. and mrs. garcia have budgeted $2800 for airplane tickets and a hotel for a family vacation. their two children will come with them on the vacation. if each round trip airplane ticket costs $415, and the hotel costs$155 per night, how many nights can the garcia's stay? write an inequality.

The inequality of nights can Garcia stay is ≤ 7 nights

Solution:

Given, Mr. And Mrs. Garcia have budgeted $2800 for airplane tickets and a hotel for a family vacation.

Each round trip airplane ticket costs $415, and the hotel costs$155 per night,  

We have to find how many nights can the Garcia's stay? Write an inequality.

Now, tickets cost for 4 members= 4 x 415 = 1660

Then, remaining budget = 2800 – 1660 = 1140

We can neglect fractional value, then, number of nights they can stay = 7

So, inequality for number of nights they will stay ≤ 7.

Hence, they can stay ≤ 7 nights.

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step-by-step explanation: