Which value must be added to the expression x2 – 3x to make it a perfect-square trinomial?
3/2
9/4
6
9

The value that must be added to the expression to make it a perfect square is (b) 9/4

The expression is given as:

Represent the coefficient of x with k.

So, we have:

Divide both sides of the equation by 2

Take the square of both sides

Evaluate the squares

Hence, the value that must be added to the expression to make it a perfect square is (b) 9/4

Read more about perfect squares at:

link

Step-by-step explanation:

Given

x² - 3x

To make the expression a perfect square

add ( half the coefficient of the x- term )²

x² + 2( - )x + , thus

x² - 3x +

= (x - )² ← a perfect square

560

step-by-step explanation:

giggidy

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: