In a certain algebra 2 class of 21 students, 14 of them play basketball and 9 of them play baseball. there are 3 students who play neither sport. what is the probability that a student chosen randomly from the class plays basketball or baseball?

basketball= 66.66 infinite%

baseball=42.86%

Step-by-step explanation:

if you divide 14 by 21 you get .66 infinite which is 66.66 infinite%

divide 9 by 21 you get around .4286 which is 42.86%

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: