40 pts! consider this quadratic equation. x^2+2x+7=21 the number of positive solutions to this equation is the approximate value of the greatest solution to the equation, rounded to the nearest hundredth, is

x2 + 2x + 7 = 21

Set it equal to zero by subtracting 21 from both sides

x2 + 2x + 7 - 21 = 21 - 21

x2 + 2x - 14 = 0

Use the quadratic equation:

x = (-b +- ( b^2 - 4ac)^1/2)/2a

In our equation a = 1, b = 2 and c = - 14

(-2 +-(4 + 56)^1/2)/2

x = -1 +- (60^1/2)/2

There is one positive solution to this equation

and it is 2.87

Hope it helps

2

step-by-step explanation:

1x2=2

hope this !

-payshence

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.