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![\text{The geometric mean formula:}\\\\\sqrt[n]{a_1\cdot a_2\cdot a_3\cdot...\cdot a_n}\\\\\text{We have}\ 6\ \text{and}\ 15.\ \text{Substitute:}\\\\\sqrt{(6)(15)}=\sqrt{90}=\sqrt{(9)(10)}=\sqrt9\cdot\sqrt{10}=3\sqrt{10}\approx(3)(3.16)=9.48](/tpl/images/0356/3789/0043f.png)
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