Iwill award

solve the equations for x:

1) a−(a+b)x=(b−a)x−(c+bx), if b≠ 0

x = if b ≠

2) 2(3x−5a)+9(2a−7b)+3(5a−2x)=0;

if a = 63b/23 then x =
if a ≠ 63b/23 then x =

1) x = (a+c)/b

2) The equation is correct no matter what value x takes.

Step-by-step explanation:

1) a−(a+b)x=(b−a)x−(c+bx)

<=> a - ax - bx = bx - ax - c - bx

<=> a - ax - bx - (bx - ax - c - bx) = 0

<=> a - ax - bx - bx + ax + c + bx = 0

<=> a - ax + ax - bx - bx + bx + c = 0

<=> a - bx + c = 0

<=> bx = a + c

If b ≠ 0, x = (a+c)/b

2) 2(3x−5a)+9(2a−7b)+3(5a−2x)=0

<=> 2×3x + 2×(-5a) + 9×2a + 9× (-7b) + 3×5a + 3×(-2x) = 0

<=> 6x -10a + 18a - 63b + 15a - 6x = 0

<=> (6x - 6x) + (15a - 10a + 18a) - 63b = 0

<=> 23a - 63b = 0

<=> 23a = 63b

=> a = 63b/23

with all values of x, the equation is correct.

1) x= (a+c)/b if b ≠ 0

2) if a =  63b23  then x = all real numbers

if a ≠  63b23  then x = no solutions

Step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: