What is the equation in slope-intercept form of the line that crossed the x-axis at 36 and is perpendicular to the line represented by y= -4/9x + 5

The equation in slope-intercept form of the line that crossed the x-axis at 36 and is perpendicular to the line represented by y = -4/9x + 5 is

Solution:

Given, line equation is

We have to find the line equation which is perpendicular to the given line in slope intercept form.

Now, let us find the slope of the given line.

Given line is in slope intercept form,  

y = mx + c where m is slope and c is intercept.

So, by comparison, slope of given line is

Now, we know that product of slopes of perpendicular lines = -1

And we are also given that, perpendicular line passes x aixs at 36. Which means that intercept of x – axis is 36.

Thus the equation in slope intercept form is found

Step-by-step explanation:

Given :

The line crossed the x-axis at 36 and is perpendicular to the line represented by

Solution :

We know that the slope intercept form is

y = mx + c ---- (1)

Given that the line is perpendicular to the line

We know that when two lines are perpendicular

And also given that the line crossed the x-axis at 36 therefore intercept is 36

Now put the value of m and c we get

For more information, refer the link given below

link

both equations and proportions are better.