.
. Let us apply logarithm on both sides of the above equation.
and 
, 
.
(1 + 2log x) – log y
log(1 + 2x) – log y
Mathematics, 01.11.2019 16:31 vonteee2
If t = 10x^2/y, then log t is equivalent to
(1 + 2log x) – log y
log(1 + 2x) – log y
(1 - 2log x) + log y
2(1 - log x) + log y
Answers: 1
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You know the right answer?
If t = 10x^2/y, then log t is equivalent to
(1 + 2log x) – log y
log(1 + 2x) – log y
(1 + 2log x) – log y
log(1 + 2x) – log y
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