The force of the wind blowing on a vertical surface varies jointly as the area of the surface and the square of the velocity. if a wind of 50 mph exerts a force of 20 lb on a surface of 1/5thft2, how much force will a wind of 125 mph place on a surface of 2 ft2?

a force of 1250lb is exerted

Step-by-step explanation:

since the force of the wind varies jointly as the area of the surface and the square of the velocity,

let f = force

a = area

velocity =v

from the above statement, we find out that

----1

that is     -----2

where k is a coefficent of proportionality

since velocity of wind in mph,v =50

and force in lb = 20

and surface area =

from eqn 2

we have that

making k subject of the formula

we have that

that means that  ---3

however, when velocity = 125mph

surface area =

putting values in eqn 3 we have

hence a force of 1250lb is exerted

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: