Arectangular parking lot has a perimeter of 364 feet. the length is 34 feet less than twice the width. set up the equation and solve for the length of the lot

Width of parking lot=72 feet

Length of parking lot=110 feet

Step-by-step explanation:

Step 1: Derive expressions for the length and width

width=x

length=y, but 34 feet less than twice the width=2 x-34

length=2x-34

Step 2: Derive expression for perimeter

Perimeter of a rectangle is given by;

P=2(L+W)

where;

P=perimeter of rectangle

L=length

W=width

in or case;

P=364 feet

L=2x-34

W=x

replacing;

2(2x-34+x)=364

4x-68+2x=364

4x+2x=364+68

6x=432

x=432/6

x=72

Width=x=72 feet

Length=2x-34=(2×72)-34=144-34=110 feet

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step-by-step explanation: