Rework problem 17 from section 5.1 of your text, involving the production of basketballs. assume that the number of defective basketballs produced is related by a linear equation to the total number produced. suppose that 9 defective balls are produced in a lot of 275, and 17 defective balls are produced in a lot of 450. find the number of defective balls produced in a lot of 675 balls.

22balls

Step-by-step explanation:

Using the method of equality,

Since 9 defective balls are produced in a lot of 275, and 17 defective balls are produced in a lot of 450, and let 'x' be number of defective balls produced out of lot of 675.

So then have;

9 balls = 275lots ...eqn 1

17 balls = 450 lots...eqn 2

x balls = 675 lots...eqn 3

To calculate x, we cross multiply any two out of the three equations. Using eqn 2 and 3,

17 balls = 450 lots...eqn 2

x balls = 675 lots...eqn 3

450x = 17×675

x = 17×675/450

x= 22balls

207/8 is the right

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11