1.) what is the equation, in standard form, of the path of firework #1?

2.) what is the equation, in vertex form, of the path of firework #2?

3.) what is the domain and range of firework #1?

Part 1)

Part 2)

Part 3) The domain of firework #1 is the interval (-∞,∞) and the range is the interval (-∞,50]

Step-by-step explanation:

1.) What is the equation, in standard form, of the path of firework #1?

we know that

The equation of a vertical parabola in vertex form is equal to

where

a is a coefficient

(h,k) is the vertex

In this problem we have

The vertex is the point (10,50)

substitute

we have the roots

(0,0) and (20,0)

For x=0,y=0

substitute in the equation and solve for a

substitute

Convert to standard form

A quadratic equation in standard form is equal to

so

2.) What is the equation, in vertex form, of the path of firework #2?

we know that

The equation of a vertical parabola in vertex form is equal to

where

a is a coefficient

(h,k) is the vertex

In this problem we have

The vertex is the point (10,72)

substitute

we have the root

(22,0)

For x=22,y=0

substitute in the equation and solve for a

substitute

3.) What is the domain and range of firework #1?

we know that

The domain of firework #1 is the interval (-∞,∞)

All real numbers

The range of firework #1 is the interval (-∞,50]

All real numbers less than or equal to 50

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

ask the math teacher she or he would know lol.

step-by-step explanation: