Which of the following points is in the solution set of y < x2 - 4x + 3? (-3, 0) (1, 0) (2, -1)

(-3,0) and (2,-1)

Step-by-step explanation:

For (-3,0)  x=-3 , y=0:

Putting in given inequality :

y < x2 - 4x + 3

0 < -3^2 -4*-3 +3     ("-" into "-" becomes "+")

0 <  9 +12 +3

0< 24   true

For (2, -1)  x=2 , y= -1

Putting in given inequality :

y < x2 - 4x + 3

-1 < 2^2 -4(2) +3

-1 < 4 -6 +3

-1 < 7-6

-1 < 1  true

For (1,0)  x=1 y=0

Putting in given inequality :

y < x2 - 4x + 3

0 < 1^2 -4(1)+ 3

0< 1- 4 + 3

0< 4 - 4

0 < 0  false

Hence, (-3,0) and (2,-1) are in the solution set of y < x2 - 4x + 3.

I hope it will help you!

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

add 5 subtract 1

step-by-step explanation: