Two planes, which are 1965 miles apart, fly toward each other. their speeds differ by 55mph. if they pass each other other in 3 hours, what is the speed of each?

The speed of the planes are 300 miles per hour and 355 miles per hour.

Solution:

Given, Two planes are 1965 miles apart, flying toward each other.  

Their speeds differ by 55 mph.  

They pass each other in 3 hours,  

We have to find what is the speed of each?

Let the speed of 1st plane be s miles per hour, then speed of the other plane will be s + 55 miles per hour.

And, distance travelled by 1st plane be d, then distance travelled by other plane will be 1965 – d miles

Now, we know that, distance = speed time

So, for 1st plane ⇒

For 2nd plane ⇒

By using 1st plane equation

1965 – 3s = 3s + 165  

1965 – 165 = 3s + 3s

6s = 1800

s = 300

So, speed of 1st plane is 300 miles per hour, then speed of 2nd plane  will  be 300 + 55 = 355 miles per hour.

Hence, the speed of the planes are 300 miles per hour and 355 miles per hour.

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3