The length of a rectangle is
2m

longer than its width.
if the perimeter of the rectangle is
48m

, find its length and width.

Perimeter is found by multiplying the length by 2 and adding it to the width multiplied by 2.

The formula is P = 2L + 2W

The length is 2m more than the width, which would be written as W +2

Now the formula is P = 2(W+2) + 2W

Replace P with the given perimeter and solve:

48 = 2(W+2) +2W

Simplify:

48 = 2W +4 + 2W

48 = 4W +4

Subtract 4 from both sides:

44 = 4W

Divide both sides by 4:

W = 11

Now you have the width solve for the length.

Length = Width +2 = 11 + 2 = 13

Check: 2(11) + 2(13) = 22 + 26 = 48

This works out to be true.

Length = 13 m

Width = 11 m