2i^4−5i^3+3i^2+√−81 rewritten in a+bi form?

-1 + 14i.

Step-by-step explanation:

i^2 = -1.

i^4 = i^2 * i^2

= -1 * -1 = 1.

i^3 = i^2 * i = -i.

√−81 = i√81 = 9i.

So

2i^4−5i^3+3i^2+√−81

= 2 - (5 * -i)  - 3 + 9i

= -1 + 5i + 9i

= -1 + 14i.

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

happy to

pls mark as brainliest