Determine the type and number of solutions of x^2 + 2x + 3 = 0.
one real solution
two imaginary solutions
two real solutions

The equation has 2 imaginary solutions

Step-by-step explanation:

x² + 2x + 3 = 0

D = b² - 4ac

= 2² - 4(1)(3)

= -8

< 0

D>0 (2 real solutions)

D=0 (1 real solution)

D<0 (2 imaginary or no real

solutions)

(Correct me if i am wrong)

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a