Find three consecutive even integers have a sum of 48.

14, 16, 18

Step-by-step explanation:

x + (x+2) + (x+4)= 48

3x + 6 = 48

3x = 42

x = 14

x+2 = 16

x+4 = 18

14, 16 and 18

Step-by-step explanation:

let the numbers be defined as x, x+2 and x+4.

Now,

x+x+2+x+4=48

3x+6=48

subtract 6 from both sides

3x=48-6

3x=42

divide both sides by 3

x=42/3=14

therefore

x=14

x+2=16

X+4=18

Hence, the numbers are 14, 16 and 18.

the answer is n