Solve the following

4 logx + 8 logy = 5
6 logx - 6 logy = -3

4 logx + 8 logy = 5

6 logx - 6 logy = -3 (divide both sides by 6)

logx - logy = -1/2

logx = logy - 1/2 (plug into the first eq)

4(logy - 1/2) + 8logy = 5

4logy - 2 + 8logy = 5

12logy = 7

logy = 7/12

y = 10^(7/12) ~ 3.831

logx = logy - 1/2 = 1/12

x = 10^(1/12) ~ 1.212

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

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